Dubious dishonour: Tupac Shakur’s aunt is the first woman on FBI’s ‘Most Wanted List’
Both the FBI and State of New Jersey are offering $1m each for information that leads to her capture
Tupac Shakur's aunt has made history by being the first woman on the Federal Bureau of Investigation's 'Most Wanted List'.
Assata Shakur has been on the run since 1979. She had murdered policeman Werner Foerster in 1973 and was convicted of murder in 1977. She shot Foerster in the head on the New Jersey turnpike after he and his partner pulled over her vehicle for a broken light. Foerster was shot in the head twice and died instantly; Zayd Shakur, Assata's partner, was also killed in the shootout. Assata Shakur and State Trooper Harper were both injured as a result of the fight.
Just two years later, she managed to escape from prison. She's been on the run ever since and is believed to be living in Cuba under political asylum.
35 years later, Shakur is now on the FBI's Most Wanted List with a reward of $2 million (£1.2 million) being offered for her capture.
While the FBI is offering $1,000,000, the State of New Jersey is also offering an additional $1,000,000 for information leading to her capture. Both agencies are asking for information only because they believe Shakur to be highly dangerous. They also believe she's connected to international terror organisations.
New Jersey State Police Superintendent Col. Rick Fuentes said in a recent news conference: "She continues to flaunt her freedom in the face of this horrific crime."